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Katen [24]
3 years ago
7

the container that holdsfor football team is 1/4 full. after pouring in 9 gallons of water it is 5/8 full. how many gallons can

the container hold?
Mathematics
1 answer:
mina [271]3 years ago
4 0

The container used to be 1/4 full, nd when you put in 9 gallons, it is 5/8 full.

First, we should have the fractions have the same denominator

1/4 = 2/8

5/8

We subtract

5/8 - 2/8 = 3/8

So if we add in 9 gallons, 1/8 of the container would be 3 gallons.

2/8 = 6 gallons

6 + 9 = 15 gallons

8/8 - 5/8 = 3/8

3/8 = 9 gallons

15 + 9 = 14 gallons

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Ayesha is on her way home in her car. She has driven
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The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

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Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

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∠C = 90°

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AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

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Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

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                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

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Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

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