Answer:
148
Explanation:
According to Hardy-Weinberg equilibrium,
p + q = 1
p² + 2pq + q² = 1 where,
p = frequency of dominant allele
q = frequency of recessive allele
p² = frequency of homozygous dominant genotype
2pq = frequency of heterozygous genotype
q² = frequency of homozygous recessive genotype
Here,
Total population = 592
Number of NN people = 148
Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25
q = √0.25 = 0.5
p = 1 - q
= 1 - 0.5 = 0.5
Hence, p = 0.5
Frequency of MM genotype = p² = 0.25
Number of people with MM genotype = 0.25*592 = 148
Hence, 148 people will have MM genotype or M blood group.
The dominant RR (red) and recessive rr (white). The color pink seems to be an intermediary between the dominant and recessive parent. Thus a heterozygote (Rr) that contains both a dominant and recessive gene will have a pink color.
Answer:
<h2>(14+16)/1000 *100= 3</h2>
Explanation:
Parental combinations are always more common then other recombinant progenies.
A female fly is heterozygous for three X-linked genes crossed with an abc/Y male. . If single crossover occurs between a & b and between b & c, then the double cross is that, which occurs in both.
Double cross over progeny are always least in number, so here double cross occurs are in abC 14 and ABc 16.
So we are expecting that number of double cross over progeny= (14+16)/1000 *100= 3
