rancho middle school has an average of 23 3/8 students per teacher write this mixed number as a decimal

Mathematics

1 answer:

Reika [66]3 years ago

6 0

let's firstly convert it to an improper fraction.

$\bf \stackrel{mixed}{23\frac{3}{8}}\implies \cfrac{23\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{187}{8}}\implies 187\div 8\implies \stackrel{decimal}{23.375}$

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Can someone plz help me with this

slava [35]

Answer:

Step-by-step explanation:

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2b. f(-2) = 3(-2)^2-(-2)^3 -2 +1 = 3(4) - (-8) -2 +1

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2 years ago

Evaluate the expression when r = 8.2 and s = –3.7.

kiruha [24]

When you plug in the numbers for the integers, you get
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3 years ago

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Brilliant_brown [7]

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3 years ago

Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b

kherson [118]

Given that 3 cards are dealt without replacement in a standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that all three cards are queens is given by

$\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}$

Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.

Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17

Part D:

Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, if two of the three cards are queens ,the probability that you will be dealt three queens is given by 2 / 50 = 1 / 25 = 0.04

Part E:

Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96

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3 years ago

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Yakvenalex [24]

Answer:

Step-by-step explanation:

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" ^ " to indicate exponentiation.

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So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."

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3 years ago

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