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Evgesh-ka [11]
3 years ago
6

Which expressions are equivalent when m = 1 and m = 4? 5 m minus 3 and 2 m 5 m 3 m 4 and m 4 2 m 2 m 7 and 3 m minus 3 m 5 m 3 a

nd 4 m 2 2 m.
Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0

The expressions that are equivalent when m = 1 and m = 4 is;

Option B: 3m + 4 and m + 4 + 2m

We are given m = 1 and m =4;

A) 5m - 3 and 2m + 5 + m

B) 3m + 4 and m + 4 + 2m

C) 2m + 7 and 3m - 3 + m

D) 5m + 3 and 4m + 2 + 2m

For option B; 3m + 4 and m + 4 + 2m

Let's put m = 1

3(1) + 4 = 7

Also, 1 + 4 + 2(1) = 7

Similarly, let us put 4 for m to get;

3(4) + 4 = 16

Also, 4 + 4 + 2(4) = 16

In both cases, the expressions are equivalent and as such option B is the right one.

Read more about algebra simplifications at; brainly.com/question/4344214

Tasya [4]3 years ago
4 0

Answer:

Step-by-step explanation:

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5 0
4 years ago
F(x)=x^2. What is g(x)
ANTONII [103]

Answer: D

Step-by-step explanation:

I substituted in the value of x (2) to see if it gave me the value of y (1) because that’s the point it gave on g(x).

The only equation that worked was D.

1/2*2=1 then 1^2=1

3 0
4 years ago
How many ways are there to move from one corner of a cube to the diagonally opposite corner, in three moves, each of which trave
Ulleksa [173]

Answer: 6 ways

there are 6 ways to move from one corner of a cube to the diagonally opposite corner in three moves

Step-by-step explanation:

Given that;

-It's restricted to three moves.

-It has to move from one diagonal to its opposite diagonal.

-it can only move through the edges.

Hence, in the first move.

We have three(3) different options that is three different possible moves that can lead us to the final destination.

The second move.

We have two (2) different possible moves each

The last move

We have just one(1) possible move.

To get the total possible ways, we will multiply the possible options for each move.

Move 1 = 3 options

Move 2 = 2 options each

Move 3 = 1 option each

3 × 2 × 1 = 6 ways

6 0
4 years ago
A
Gnesinka [82]

Answer:

A: 779 cm²

B: 1837 cm²

Step-by-step explanation:

For both problems, use the formula for surface area of a cylinder:

SA = 2πr² + 2πrh

2πr² is the two bases.

2πrh is the curved surface.

<u>PROBLEM A</u>

"the cylinder is 60 cm long" is h = 60.

If given diameter, you can find "r" by dividing it by 2. d = 2r

Given d = 4, then r = 2.

SA = 2πr² + 2πrh

SA = 2π2² + 2π2(60)

SA = 8π + 240π               Add

SA = 248π                       Exact answer

SA ≈ 779.114978             Answer on calculator

SA ≈ 779           Rounded answer

Remember to include the units.

The surface area is about 779 cm².

<u>PROBLEM B</u>

"80 cm long" h = 80.

"circumference of 22 cm". C = 22. Remember C = 2πr. Find "r".

C = 2πr

22 = 2πr

11 = πr

r ≈ 11/π

SA = 2πr² + 2πrh

SA = 2π(11/π)² + 22(80)       Substitute 2πr with the circumference.

SA ≈ 1837.030992            Answer on calculator

SA ≈ 1837               Rounded answer

Remember to include the units.

The surface area is about 1837 cm².

7 0
4 years ago
What are the zero(s) of the function f(x)=4x2-36x over x-9?
vfiekz [6]
F(x) = (4x^2 - 36x) / (x-9)
0 = 4x * (x-9) / (x-9)
0 = 4x

x=0
hope this helps
7 0
3 years ago
Read 2 more answers
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