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Evgesh-ka [11]
2 years ago
6

Which expressions are equivalent when m = 1 and m = 4? 5 m minus 3 and 2 m 5 m 3 m 4 and m 4 2 m 2 m 7 and 3 m minus 3 m 5 m 3 a

nd 4 m 2 2 m.
Mathematics
2 answers:
emmasim [6.3K]2 years ago
4 0

The expressions that are equivalent when m = 1 and m = 4 is;

Option B: 3m + 4 and m + 4 + 2m

We are given m = 1 and m =4;

A) 5m - 3 and 2m + 5 + m

B) 3m + 4 and m + 4 + 2m

C) 2m + 7 and 3m - 3 + m

D) 5m + 3 and 4m + 2 + 2m

For option B; 3m + 4 and m + 4 + 2m

Let's put m = 1

3(1) + 4 = 7

Also, 1 + 4 + 2(1) = 7

Similarly, let us put 4 for m to get;

3(4) + 4 = 16

Also, 4 + 4 + 2(4) = 16

In both cases, the expressions are equivalent and as such option B is the right one.

Read more about algebra simplifications at; brainly.com/question/4344214

Tasya [4]2 years ago
4 0

Answer:

Step-by-step explanation:

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daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

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Answer:

A. AAS

Step-by-step explanation:

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Hello can you please help me with it I don't really understand this question
9966 [12]

Answer:

see explanation

Step-by-step explanation:

solving the inequality

\frac{x}{5} ≥ 8 ( multiply both sides by 5 to clear the fraction )

x ≥ 40

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8 0
2 years ago
Yoshi wrote the standard form for three hundred sixty and nine hundred seven thousandths .Kim wrote a number with 3 more ones an
eduard

Yoshi wrote the standard form for three hundred sixty and nine hundred seven thousandths. This is the number 360.907. This number consists of 3 hunreds, 6 tens, 0 ones and 9 tenths, 0 hundredths, 7 thousandths.

Kim wrote a number with 3 more ones and 7 less tenths.

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Actually Kim wrote 363.207 (see added place value table).

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When making a choice, we give up costs, and we gain? (Economics)
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