The team plays 20 matches.
65% of the matches, the teams wins
= 20 * 0.65
= 13 matches
15% of the matches, the games ends in draw.
= 20 * 0.15
= 3 matches
The team is expected to lose in
= 20 - 13 - 3
= 4 matches
I think it's 9 but I could be wrong
Answer:
The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
the maximum value of t(x) is greater than the maximum value of g(x)
