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gizmo_the_mogwai [7]
3 years ago
10

Pleaseee help asapppp

Mathematics
1 answer:
shusha [124]3 years ago
3 0
Ok done. Thank to me :>

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What is 10x+7=147;14,15,16
gizmo_the_mogwai [7]

10x + 7 = 147
1st step you subtract 7 from both sides and the 7 get cancelled so you will get
10x = 140
2nd step you divide by 10 from both sides so you will get

x = 14

3rd step is that you final answer is
x = 14
4 0
3 years ago
Find the slope of the line that passes through (10,8) and (4,3)
ladessa [460]

Answer: 5/6

Step-by-step explanation: If you graph out the relation and you do rise/run. You get 5 for the rise and 6 for the run.

Hope this helps! Please mark me brainiest.

8 0
3 years ago
Find the slope of the equation of the line that passes through the given points. through: (0, -3) and (3, 4)
Nadya [2.5K]

Answer:

7/3

Step-by-step explanation:

The slope is found by dividing the difference in the y-coordinates by the difference in the x-coordinates.

Here, the difference in the y-coordinates is: 4 - (-3) = 4 + 3 = 7. The difference in the x-coordinates is: 3 - 0 = 3.

Dividing 7 by 3, we get a slope of 7/3.

5 0
3 years ago
Read 2 more answers
What is the volume of a sphere with a radius of 9 inches?
OLga [1]
Volume of a sphere: (4/3)πr³
r=radius=9 in

Volume=(4/3)*π*(9 in)³=972π cubic inches≈3053.63 in³

answer: D) 972π cubic inches  (3053.63 in³ is correct)


3 0
3 years ago
what are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution
Darina [25.2K]

Consider the given quadratic equation 50-x^2=0

x^2-50=0

Comparing the given quadratic equation to the general equation ax^2+bx+c=0, we get a= 1, b=0 and c= -50

So, the solution to the quadratic equation is given by:

x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}

x = \frac{-0 \pm \sqrt{0^2-4(1)(-50)}}{2}

x = \frac{\pm \sqrt{200}}{2}

x = \pm \sqrt2 (5)

x = \pm 5\sqrt2

So, the solutions to the given quadratic equation are x = \pm 5\sqrt2.

5 0
3 years ago
Read 2 more answers
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