Explanation:
#include <iostream.h>
#inlcude<conion.h>
void main()
{
int count, x;
clrscr();
cout<<"Enter the count:";
cin>> count;
cout<<"Ready!\n";
for(x=count;x>0;x--)
{
cout<<x<<"\n";
}
cout<<"Start";
getche();
}
This is a simple program where the output is expected to be in reverse order. So we run a for loop starting from the count and decrements the counter by 1 every time when the loop runs and print the value. So to print the output in "new line" we include "\n".
Here is a Python program:
tmp = input().split(' ')
c = tmp[0]; s = tmp[1]
ans=0
for i in range(len(s)):
if s[i] == c: ans+=1
# the ans variable stores the number of occurrences
print(ans)
One approach to solving this is to first calculate the current the will flow through all three resistors:
The total resistance is R1+R2+R3 = 5280
I = V/R = 30/5280 ≈ 5,682 mA
Then the drop across R2 = I*R2 = 5,7mA * 1000 ≈ 5.682 V.
So this is based on the fact that V=I*R and there is one current running in the entire chain, ie., it is the same through each resistor.
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