1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
quester [9]
3 years ago
8

The value -2 is a lower bound for the zeros of the function shown below.

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

False

Step-by-step explanation:

f(x) = 4x³ - 12x² - x + 15

Set output to 0.

Factor the function.

0 = (x + 1)(2x - 3)(2x - 5)

Set factors equal to 0.

x + 1 = 0

x = -1

2x - 3 = 0

2x = 3

x = 3/2

2x - 5 = 0

2x = 5

x = 5/2

-2 is not a lower bound for the zeros of the function.

You might be interested in
Josh saved 1/4 of his pocket money and spent 1/2 of the remainder. What fraction did he spend
slavikrds [6]
Ok so since Josh spent 1/2 of his money I assume you will be subtracting in this specific question. So 1/4 - 1/2. The first step in solving this is that you want both fractions to have the same denominator. So you have to ask yourself what factor does 4 and 2 share in common. They both share the number 4 in common. So you will have to set the denominators as 4 now. Now for 1/2 you get 2/4 when you multiply both the numerator and denominatorby 2. Now you will have to do the same thing for the fraction 1/4 so the new fraction you will get when you multiply the numerator and denominator by 1 is 1/4. So now you have 1/4-2/4. Ok so your answer shouldbe 1/4. I realized I should of put the fraction 2/4 first. I hoped that helped!!!!
8 0
3 years ago
Choose between ones that are slashed
denis-greek [22]
\textbf{You have to} restrict the domains of quadratic functions and absolute value functions, because these functions are \textbf{many-to-one} functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.

Linear functions (excluding constant functions) and exponential functions are \textbf{one-to-one} functions, so their domains \textbf{do not need} to be restricted.
_________________

An absolute value function, without domain restriction, has an inverse that is NOT a function.

In order to guarantee that the inverse must also be a function, we need to restrict the domain of the absolute value function to make it a one-to-one function.
5 0
3 years ago
N
Vaselesa [24]

Answer:

75(1/3)^(n-1).

Step-by-step explanation:

This is a Geometric sequence whose common ratio is  15/75 3/15 = 1/3.

so the nth term  an = a1 r^(n-1)

= 75(1/3)^(n-1).

6 0
3 years ago
MATCHING: Compare the fractions from Column B to the given percent's in Column A. Match the fractions that are the closest value
emmasim [6.3K]

Answer: someone please help bc i have no idea

Step-by-step explanation: bad werewolf

7 0
3 years ago
Read 2 more answers
6^5x=20 round to the nearest ten-thousands
natulia [17]
Ok so 6^5
6x6x6x6x6 = 7776

7776x=20

Then we divide each side by 7776

7776x = 20
——— ———
7776 7776


X= 0.00257202


Estimate: 0
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the the domain and range of f^-1 where f(x)=1/(3x+2)
    15·1 answer
  • Find a positive angle less than one rotation that is coterminal with 750 degrees
    9·1 answer
  • What percentage of this grid is shaded
    10·2 answers
  • Cassie wants to use green and yellow fabric to make some curtains. She has 28.85 yards of yellow fabric and 34.25 yards of green
    9·2 answers
  • Find the sum. ???? 2 0<br> −2 3<br> ???? + ????1 5<br> 0 1<br> ????
    6·1 answer
  • Which is true of the population shown in this graph?
    11·2 answers
  • Porfavor se los agradeceria mucho y de corazon :D
    6·1 answer
  • Help please!!!!!A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history book. what is
    14·1 answer
  • Help me answer this question
    12·1 answer
  • Dilate the given line segment by a scale factor of 0.5 with a center of dilation at the origin. Draw the dilated segment on the
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!