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4 years ago

How does the graph of f(x)=4 cos(1/2x)-3 differ from the graph of g(x)=4 cos(x)-3

Mathematics

2 answers:

just olya [345]4 years ago

8 0

Answer:

The function f(x) is stretched horizontally.

Step-by-step explanation:

We are asked to determine how the graph of $f(x)=4\text{cos}(\frac{1}{2}x)-3$ differ from the graph of $g(x)=4\text{cos}(x)-3$ .

Let us recall transformation rules of functions.

$f(ax)\rightarrow$

If $a>1$ function compresses horizontally.

If $a$ function stretches horizontally.

Upon looking at function $f(x)=4\text{cos}(\frac{1}{2}x)-3$ , we can see that the value of 'a' is less than 1 that is $\frac{1}{2}$ , therefore, the function f(x) is stretched horizontally.

Sunny_sXe [5.5K]4 years ago

5 0

The graph of f(x)=4 cos(1/2x)-3 differs from the graph of g(x)=4 cos(x)-3, f(x) is stretched horizontally.

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What is the solution to to the equation x − 2/5 = −1?

ZanzabumX [31]

Answer:

x = -0.6

Step-by-step Solution:

Isolate the variable x to get the answer.

x − 2/5 = −1
=> x = -1 + 2/5
=> x = -1 + 0.4
=> x = -0.6

Hence, the value of x is -0.6.

6 0

2 years ago

Read 2 more answers

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

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$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

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$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

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$x -10 + 10 < 0 +10$

$x < 10$

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$-5x \cdot 11 < 31$

$-55x < 31$

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$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

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3 years ago

Evaluate y = 2x + 1 when x = 1

Solnce55 [7]

Answer:

y = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

y = 2x + 1

x = 1

Step 2: Evaluate

Substitute in x: y = 2(1) + 1
Multiply: y = 2 + 1
Add: y = 3

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3 years ago

Which is a right triangle formed using a diagonal through the interior of the cube? A cube. The top face has points G, B, C, F a

Black_prince [1.1K]

Answer: The correct option is triangle GDC

Step-by-step explanation: Please refer to the picture attached for further details.

The dimensions give for the cube are such that the top surface has vertices GBCF while the bottom surface has vertices HADE.

A right angle can be formed in quite a number of ways since the cube has right angles on all six surfaces. However the question states that the diagonal that forms the right angle runs "through the interior."

Therefore option 1 is not correct since the diagonal formed in triangle BDH passes through two surfaces. Triangle DCB is also formed with its diagonal passing only along one of the surfaces. Triangle GHE is also formed with its diagonal running through one of the surfaces.

However, triangle GDC is formed with its diagonal passing through the interior as shown by the "zigzag" line from point G to point D. And then you have another line running from vertex D to vertex C.