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givi [52]
3 years ago
10

How does the graph of f(x)=4 cos(1/2x)-3 differ from the graph of g(x)=4 cos(x)-3

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer:

The function f(x) is stretched horizontally.

Step-by-step explanation:

We are asked to determine how the graph of f(x)=4\text{cos}(\frac{1}{2}x)-3 differ from the graph of g(x)=4\text{cos}(x)-3.

Let us recall transformation rules of functions.

f(ax)\rightarrow

If a>1 function compresses horizontally.

If a function stretches horizontally.

Upon looking at function f(x)=4\text{cos}(\frac{1}{2}x)-3, we can see that the value of 'a' is less than 1 that is \frac{1}{2}, therefore, the function f(x) is stretched horizontally.

Sunny_sXe [5.5K]3 years ago
5 0
The graph of f(x)=4 cos(1/2x)-3 differs from the graph of g(x)=4 cos(x)-3, f(x) is stretched <span>horizontally.</span> 
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