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4 years ago

What do f(n) and f(n-1) represent in a sequence?

Mathematics

1 answer:

Natalka [10]4 years ago

4 0

Answer:

f(n) is the function f-1(n) is the inverse of that function , basically the x and y switch places

Step-by-step explanation:

You might be interested in

Locate the vertical asymptotes, and sketch the graph of y = sec (x - π) + 3.

8_murik_8 [283]

Since secant is the inverse of cosine function, when the cosine function has a 'zero' the secant will have a vertical asymptote.

Graphing a cosine with a right shift of pi, the zeros would be at pi and 2pi.
This will make the vertical asymptotes of the secant function be at pi and 2pi.

I hope you understand.

6 0

4 years ago

5+15x=5( ) I'm not writing 20 characters

kompoz [17]

Answer:

(1 + 3x).

Step-by-step explanation:

We have to evaluate the missing term within the brackets in the following equation.

The equation is, 5 + 15x = 5(?)

Now, 5 + 15x

= 5 × 1 + 5 × 3x {We have to factorize the term where 5 is a factor}

= 5(1 + 3x) {This is reverse of the distributive property of multiplication}

Therefore, the missing term within the brackets is (1 + 3x). (Answer)

6 0

3 years ago

What is 10 divied by 7/8

Zielflug [23.3K]

Answer:

11.43

Step-by-step explanation:

10 divided by 7/8

Set the expression:

(10/(7/8))

To solve, flip the denominator fraction, and make the division into multiplication:

((10 x 8)/7)

Multiply across, then divide:

(80)/7

Divide:

80/7 = 11.43 (rounded)

11.43 is your answer.

4 0

4 years ago

Read 2 more answers

1. Write an equation in slope-intercept form of the line that passes through the given points.

MrRissso [65]

I wrote the answers in the pictures...

5 0

3 years ago

Please help!

BaLLatris [955]

a) The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) There is a discontinuity at $x = 2$ with a slant asymptote.

a) In this question we are going to use the Factor Theorem, which establishes that polynomial are the result of products of binomials of the form $x-r_{i}$ , where $r_{i}$ is the i-th root of the polynomial and the grade is equal to the quantity of roots. Therefore, the polynomial $f(x)$ has the following form:

$f(x) = (x-6)\cdot (x+1)\cdot (x+3)$

And the expanded form is obtained by some algebraic handling:

$f(x) = (x-6)\cdot (x^{2}+4\cdot x +3)$

$f(x) = x\cdot (x^{2}+4\cdot x + 3)-6\cdot (x^{2}+4\cdot x +3)$

$f(x) = x^{3}+4\cdot x^{2}+3\cdot x -6\cdot x^{2}-24\cdot x -18$

$f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ (1)

The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) In this question we divide the polynomial found in a) (in factor form) by the polynomial $x^{2}-x -2$ (also in factor form). That is:

$g(x) = \frac{(x-6)\cdot (x+1)\cdot (x+3)}{(x-2)\cdot (x+1)}$

$g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ (2)

The slant asymptote is defined by linear function, whose slope ( $m$ ) and intercept ( $b$ ) are determined by the following expressions:

$m = \lim_{x \to \pm \infty} \frac{g(x)}{x}$ (3)

$b = \lim_{x \to \pm \infty} [g(x)-x]$ (4)

If $g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ , then the equation of the slant asymptote is:

$m = \lim_{x \to 2} \frac{(x-6)\cdot (x+3)}{x\cdot (x-2)}$

$m = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x^{2}-2\cdot x} \right)$

$m = 1$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x-2}-x \right)$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x - 18-x^{2}+2\cdot x}{x-2}\right)$

$b = \lim_{n \to \infty} \left(\frac{-x-18}{x-2} \right)$

$b = -1$

The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) The number of discontinuities in rational functions is equal to the number of binomials in the denominator, which was determined in b). Hence, we have a discontinuity at $x = 2$ with a slant asymptote.

We kindly invite to check this question on asymptotes: brainly.com/question/4084552

8 0

2 years ago