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dolphi86 [110]
3 years ago
13

What combination of transformations is shown below?

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

d)rotation then reflection

Step-by-step explanation:

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Solve for x 3x-3>x+7
Sever21 [200]

Answer:

x>5

Step-by-step explanation:

6 0
3 years ago
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
What is the solution of the system?
Phoenix [80]

Answer:

(-2, 6)

Step-by-step explanation:

We can simply do this by plugging in all of the coordinates. (I did this in my head quickly, so I know what it is; I'm just going to plug in the correct answer.) The correct answer is (-2, 6), so we're just going to plug them into the simplest equation, which is probably y=-3x. So...

6=-3(-2)

6=6

This answer is correct. If you're unsure about the answer, you can always check in the other equation. So...

3(-2)+2(6)=6

-6+12=6

6=6

Hope this helps and have an amazing day ^^

5 0
3 years ago
Read 2 more answers
The rock band, Screamin’ Meanies, has a fan club that publishes a monthly newsletter. Expenses are $.35 for printing and mailing
NemiM [27]
2 days to get this apology. its really does suck to not get your question answered in the firs ten min  <span />
7 0
3 years ago
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To fill out a sign chart, you will need to use test numbers before and after each of the function's zeros and ___
Vikki [24]

Answer:

C. asymptotes

Step-by-step explanation:

In the figure attached, a sign chart is shown. To fill it out you need to find the function's zeros and asymptotes. The zeros are those x values that makes the function equal to zero, in the example, those are the x values that make the denominator equal to zero (x = -1 and x = 5). In a rational function, the asymptotes are those x values that make the numerator equal to zero (x = -9 in the example)

Function in the example:

\frac{(-2x-2)(2x-10)}{-9x-81}

7 0
3 years ago
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