P=25,000÷(1+0.0425)^(18)
P=11,818.73
So the answer is b
2(2)2(3)2(4)=192 because you're multiplying everything together in order to find your answer and also because the variables which are the letters represent the numbers that need to be multiplied idk if that made sense but that's the answer lol
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
3/5 3/4 7/8
As the higher the denominator and the higher the numerator or 'parts filled', the greater the fraction.
Answer: A, 1/2
Step-by-step explanation:
he is simply using 1 cup of bs for each cup of ws so when you do it its i cup of ws then its hald of 1 bs