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djverab [1.8K]
3 years ago
5

To receive a C grade, a student must average more than 77 but less than or equal to 85. If Ethan received a C in the course and

had five grades of 74, 78, 76, 67, and 85 before taking the final exam, what were the possible grades for his final if there were 100 points possible? (Assume all six grades are weighted equally and let x represent the unknown score.)
Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

So for his mark will be in between 82 to 130 for C grade

Step-by-step explanation:

We have given that for C grade the minimum average mark should be 77 and maximum average mark should be 85

There are 6 subjects

So total minimum mark = 6×77 =462

And total maximum mark = 85×6 =510

He has five grades as 74,78,76,67,85

So sum of five grades = 74+78+76+67+85=380

Let he get x marks in 6th

So for minimum mark in 6th grade  x+380 = 462

x = 462-380=82

For maximum mark x+380=510

x = 510-380 =130

So for his mark will be in between 82 to 130 for C grade

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attashe74 [19]

Answer:

The median is 9

The Range is 13-5=8

The mean is 5+5+9+11+13/5=43/5=8 3/5=8.6

5 0
2 years ago
A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
Find the circumference of a circle with a radius of 6 miles. The circumference is __mi.
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Answer: yall boys go add me on tha gram

Step-by-step explanation:

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3 years ago
Yes I need help plz<br><br><br><br><br><br><br><br> !!!!!!!!!!!
Delicious77 [7]

Answer:

Slope = -2

Step-by-step explanation:

slope = (y₂ - y₁)/(x₂ - x₁)

s = (6 - 0)/(-3 - 0)

s = 6 / -3

s = -2


I hope this helped and please mark me as brainliest!

4 0
3 years ago
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astra-53 [7]

Answer:

348

Step-by-step explanation:

Length-l

Width-w  

Height-h

A=2(wl+hl+hw)=2·(8·9+6·9+6·8)=348

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3 years ago
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