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3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics

1 answer:

Anton [14]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

j - 4 ≤ 0 ( add 4 to both sides )

j ≤ 4

The graph has a closed circle at 4 on the number line with the arrow pointing left

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Eddie's Evergreens sells Christmas trees and wreaths. Trees cost 3 dollars more than 4 times the price of each wreath. It costs

kari74 [83]

Answer:

$W = 16$

$T = 67$

Step-by-step explanation:

Represent trees with T and wreaths with W

Given

$T = 3 + 4 * W$

$2 * W + T = 99$

Solving (a): Cost of W

Substitute 3 + 4 * W for T in the second equation

$2*W + 3 + 4 * W = 99$

$2W + 3 + 4 W = 99$

Collect Like Terms

$2W + 4 W = 99 - 3$

$6W = 96$

Divide through by 6

$W =\frac{96}{6}$

$W = 16$

Hence, each wreath costs $16

Solving (b): Cost of T

$T = 3 + 4 * W$

Substitute 16 for W

$T = 3 + 4 * 16$

$T = 3 + 64$

$T = 67$

Hence, each tree costs $67

3 0

2 years ago

In a warehouse, boxes have been stacked in 4 layers as shown. The workers make other stacks according to the same pattern. If a

FromTheMoon [43]

Answer:

Step-by-step explanation:

6 0

2 years ago

Find the gradient of the line segment between the points (-4,2) and (4,5).

aleksklad [387]

Answer:

Gradient is = 0.375

Step-by-step explanation:

Rise = 3

Run = 8

8 0

2 years ago

Read 2 more answers

-2x + 7 = x-32 i need all the steps

ycow [4]

Answer:

-2x + 7 = x-32

7+32=x+2x

39=3x

x=39/3

x=13

Step-by-step explanation:

5 0

2 years ago

Find the area of a square if its sides measure 2 2/3m

olga55 [171]

Answer:

$7\dfrac{1}{9}\ m^2$

Step-by-step explanation:

If the length of the square side is a units, then the area of the square is

$A=a^2\ un^2.$

In your case, the side length is

$a=2\dfrac{2}{3}\ m,$

then the area is

$A=2\dfrac{2}{3}\cdot 2\dfrac{2}{3}\\ \\ \\A=\dfrac{2\cdot 3+2}{3}\cdot \dfrac{2\cdot 3+2}{3}\\ \\ \\A=\dfrac{8}{3}\cdot \dfrac{8}{3}\\ \\ \\A=\dfrac{64}{9}\\ \\ \\A=7\dfrac{1}{9}\ m^2$

6 0

3 years ago