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Masja [62]
3 years ago
10

Jeff is building a bookcase for his room and wants to be sure the shelves are parallel. He measures the angles below and knows t

he shelves are parallel when he finds which two angles to be supplementary?

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

∠2 and ∠4 are the supplementary angle.

Step-by-step explanation:

Shelves of the bookcase are parallel and a transversal line is intersecting these points at two distinct points.

By the property,

Sum of two interior consecutive angles measure 180°.

From the figure attached,

∠2 and ∠4 are the interior consecutive angles.

Therefore, m∠2 + m∠4 = 180°

Which proves that shelves of the showcase are parallel.

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Y varies directly with x. When x is 4 y is 8. Find y when x = 10.
grandymaker [24]

Step-by-step explanation:

y = 4 when x = 8 So, 4 = 8k

k = 1/2

y = (1/2)x

Therefore, when x = 10, y = (1/2)(10) = 5

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2 years ago
Find the measure of angle x
Triss [41]

Answer:

it is heptagon and sum of interior angles of heptagon is 900 °

123°+131°+ 125°+124°+x 129°+132° = 900°

764° +x = 900 °

x = 900°-764°

x = 136°

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3 years ago
Select all of the potential solution(s) of the equation 2log5x = log54.
tankabanditka [31]

Answer:

-2 and 2

Step-by-step explanation: just did the problem

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3 years ago
Find the area of a trapezoid with bases of 15cm and 6 cm and a height of 1/5cm
NNADVOKAT [17]
Area = 0.5 x (a+b) x h

= 0.5 x (15cm + 6cm) x 1/5cm
= 0.1 x 21cm
=2.1cm^2  (2.1 centimeters squared)
8 0
3 years ago
Read 2 more answers
Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.
disa [49]

Answer:

The solutions x^4-5x^2-36=0 are x=3,\:x=-3,\:x=2i,\:x=-2i and the x-intercepts of y=x^4-5x^2-36 are x=3,\:x=-3

Step-by-step explanation:

Finding the solutions to x^4-5x^2-36 means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with u=x^2 and u^2=x^4

u^2-5u-36=0

Solve by factoring

\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)

\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)

\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)

u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)

\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)

u^2-5u-36=\left(u+4\right)\left(u-9\right)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

\:u=-4,\:u=9

Substitute back u=x^2, solve for x

x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)

Apply the difference of squares formula

x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)

(x-3)(x+3)(x^2+4)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

\:x=3,\:x=-3,\:x=2i,\:x=-2i

Because two of the solutions are complex roots the only x-intercepts are x=3,\:x=-3

3 0
3 years ago
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