2L +2W=160
100+ 2W=160
subtract 100 from each side
2W=60
divide by two each side
W=30
use the formula L×W=Area or 50×30 which equals 150 the are of the pasture is 150 feet²
1. IQR = Q3 - Q1 = 35 - 20 = 15
A. 15
3. The ages include 20 and 25 so A and C are out, and the ages are between the two ages
B. a >= 20 and a <= 25
4. With the addition of 30, there are now 14 dots. Therefore, the median will be the mean of the 7th and 8th dots from least to greatest on the number line. In this case, it would still be 22.
C. The median would stay the same.
For this case the generic equation of the line is given by:
Where,
m: slope of the line
b: intersection with the y axis
For this case we have:
Therefore, substituting values in the generic equation we have:
Answer:
The equation of the line is:
option 1
Answer:
a) markup = $3
b) markup as a percentage of cost is 33.3%
Step-by-step explanation:
<em>Markup</em>
... markup = selling price - cost
... = $12 - 9
... markup = $3
<em>Markup as a Percentage of Cost</em>
To find the percent markup, divide the markup by the reference value and multiply the ratio by 100%. The reference value for markup is usually cost price, but sometimes may be selling price.
... markup / cost × 100% = 3/9×100% = 33 1/3% ≈ 33.3%
_____
When the markup is figured as a percentage of selling price, the result is usually called <em>margin</em>. Some folks are not very careful in distinguishing markup from margin.
A+5 = 1 side, so the perimeter is 3(a+5) or P = 3a+15
