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lana [24]
3 years ago
13

What is the greatest common factor of 48, 72 and 52?A.2B.4C.8D.16

Mathematics
2 answers:
kaheart [24]3 years ago
8 0
The GCM  of 48, 72, and 52 is B.) 4
Tasya [4]3 years ago
6 0
B. 4 is the answer 8 and 16 don’t go into 52 evenly
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For 5 points and brainliest to the best correct answer, find the missing measures.<br> Thank you
zzz [600]

Answer:

  • x = 7
  • y = 97°
  • z = 19

Step-by-step explanation:

The markings on the figure show this to be a parallelogram. That means opposite sides are congruent. Because the sides are parallel, "alternate interior" angles are also congruent.

__

Angle y forms a linear pair with the one marked 83°, so is supplementary to it:

  y = 180°-83° = 97°

__

The angle marked y is an exterior angle to the triangle containing the angle marked (7x -5)°. As such, it is equal to the sum of the remote interior angles, the one marked (7x -5)° and the unmarked one that is congruent to (3x +32)°.

  (7x -5) +(3x +32) = 97 . . . . . angle relations in the left-side triangle

  10x +27 = 97 . . . . . . . collect terms

  10x = 70 . . . . . . . . subtract 27

 x = 7 . . . . . . . . divide by 10

__

The side marked Z is congruent to the opposite parallel side, so ...

  z = 19

__

The missing measures are ...

  • x = 7
  • y = 97°
  • z = 19

_____

<em>Additional comment</em>

You can also find the value of y by adding up the interior angles of the right-side triangle. The one not shown there is "alternate interior" to the one marked (7x -5)°, hence has the same measure. This gives ...

  (7x -5) +(3x +32) +83 = 180

Subtracting 83° from both sides gives the equation we used above.

4 0
2 years ago
HELP ME THIS IS DUE RN. ILL give 50 points and brainiest.
Maru [420]

Answer:

y = 8x + 21

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
Someone please help me
kirill115 [55]
It’s d 6ft

:))))))))))
7 0
3 years ago
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Suppose that you ask three friends to go to the mall. each one has a 0.80 chance of saying yes. what is the probability that all
blondinia [14]
The probability is 0.512
5 0
3 years ago
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