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3 years ago

10

3 + 3 x 3 - 3 + 3 =?

2 answers:

kifflom [539]3 years ago

8 0

Answer:

6

Step-by-step explanation:

We are going to use PEMDAS to solve this. PEMDAS stands for Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. You use it to determine the order of operations you use.

So there are no parenthesis or exponents, so we skip right to multiplication.

3+3 x 3 - 3 + 3

^ 3 x 3 = 9

So now we have 3+ 9 - 3 +3

There is no division, so lets move to addition.

3+9 - 3 + 3

^ 12 ^ 6 Our equation is now 12-6

12-6 = 6, so the answer to this equation is 6

SCORPION-xisa [38]3 years ago

3 0

12, 3x3 = 9, +3 =12-3=9+3=12

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Choose the linear inequality that describes the graph. The gray area represents the shaded region.

jek_recluse [69]

Answer:

2x + 3y ≥ 5

Step-by-step explanation:

See the graph attached.

The bold straight line passes through the points (1,1) and (4,-1).

Therefore, the equation of the straight line will be

$\frac{y + 1}{- 1 - 1} = \frac{x - 4}{4 - 1}$

⇒ 3(y + 1) = - 2(x - 4)

⇒ 3y + 3 = - 2x + 8

⇒ 2x + 3y = 5 ............. (1)

Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).

So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5

Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)

6 0

3 years ago

Estimate how many 1/3 pound boxes can be filled from a 5 3/4 lb bag of rice

Gnesinka [82]

The answer is 17 1/4 .Hope this helped.

4 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.

Setler79 [48]

Answer:

Therefore values of a and b are

$a=3\ and\ b = 2$

Step-by-step explanation:

Rewrite $x^{2}-6x+7=0$ in the form

$(x-a)^{2}=b$

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

$x^{2}-6x+7=0$ ..............Given

Which can be written as

$x^{2}-6x=-7$

$(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9$

Adding half coefficient of X square on both the side we get

$x^{2}-6x+9=-7+9=2$ ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

$x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}$

Substituting in equation 1 we get

$(x-3)^{2}=2$

Which is in the form of

$(x-a)^{2}=b$

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

$a=3\ and\ b = 2$

4 0

3 years ago

Please help :) is it linear, if so model the data with and equation.

Yuki888 [10]

Answer:

The relationship is linear: y -5 = 2 (x+7)

Step-by-step explanation:

While the difference between -7 and -5 / -5 and -3 / -3 and -1 is always 2 teh difference between 5 and 9 / 9 and 13 / 13 and 17 is always 4.

y-5 = -1/2 (x +7)

for x= -7 and y = 5 this is true

for x=-5 and y = 9 this is not true

y + 7 = 1/2 (x-5)

for x= -7 and y = 5 this is not true

y -5 = 2 (x+7)

for x= -7 and y = 5 this is true

for x = -5 and y = 9 this is true

for x = -3 and y = 13 this is true

for x = -1 and y = 17 this is true

8 0

3 years ago