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Klio2033 [76]
3 years ago
5

Suppose you invest $7500 at an annual interest rate of 4.2% compounded continuously. How much will you have in the account after

2 years? Round the solution to the nearest dollar.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Step-by-step explanation:

P=$7500

T=2yrs

R=4.2%

now,

CA=P((1–R)^T)/100

=7500(1–4.2/100)^2

then slove it on calculator and you will get the required result

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The degree is the largest exponent on the variable.

Degree: 5

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3 years ago
Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: y=mx+b where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation  y=mx+b where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

y=mx+b\\y=-\frac{2}{3}x+3

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

5 0
3 years ago
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Scientists measured the annual forest loss (in square kilometers) in Indonesia from 2000–2012. They found the regression line
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The slope of this line is 1021.

Step-by-step explanation:

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y = b + ax

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In this problem, our line is:

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So the slope of this line is 1021.

7 0
3 years ago
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
3 years ago
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