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3 years ago

Solve for the width in the formula for the area of a rectangle.

Mathematics

2 answers:

Softa [21]3 years ago

4 0

Answer:

W=A/L

2.5in

Step-by-step explanation:

kupik [55]3 years ago

4 0

Answer:

Solve for the width in the formula for the area of a rectangle.

W=A/L

Use the rewritten formula to find the width of a rectangle with an area of 42 square inches and a length of 16.8 inches.

2.5in

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STALIN [3.7K]

Answer:

x=9 and angle B=40

Step-by-step explanation:

5x-5=3x+13

Subtract -3 on both sides of x

5x(-3)-5=3x(-3)=+13

2x-5=13

Add 5 to both sides

2x-5(+5)=13(+5)

2x=18

Divide by 2

x=9

Now that you know x=9, plug it into 3x+13

So, 3(9)+13= 27+13= 40

so ya thats my answer hopefully it helps

(btw both angle A and B are the same so thats why u put them equal)

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4 years ago

The picture. and answer 1-6. please hurry

satela [25.4K]

Answer:

Step-by-step explanation:

From the figure attached,

1). Sin(D) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{EF}{DF}$

= $\frac{24}{26}$

= $\frac{12}{13}$

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= $\frac{ED}{DF}$

= $\frac{10}{26}$

= $\frac{5}{13}$

3). tan(D) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

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= $\frac{24}{10}$

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= $\frac{10}{26}$

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5). cos(F) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

= $\frac{EF}{DF}$

= $\frac{24}{26}$

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6). tan(F) = $\frac{\text{Adjacent side}}{\text{Adjacent side}}$

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3 years ago

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V125BC [204]

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4 years ago

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Answer:

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Step-by-step explanation:

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