The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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Answer:
-2x + 6
Step-by-step explanation:
Step 1: Define
f(x) = 3x + 2
g(x) = 4 - 5x
Step 2: Find f(x) + g(x)
3x + 2 + 4 - 5x
-2x + 6
Yoh...Aye it’s only gonna get harder from here tbh
Answer:
1, 4/5,2/5
Step-by-step explanation:
y = 5x
Let y = 5
5 = 5x
Divide by 5
5/5 =5x/5
1=x
Let y=4
4 =5x
Divide by 5
4/5 =5x/5
4/5 =x
Let y=2
2 =5x
Divide by 5
2/5 =5x/5
2/5 =x
Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =

So, the vertex form is (x + 2)² = 4(

)(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +

)
F(-2,

)