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3 years ago

What is the solution to the equation 4x + 2(x − 2) = 4x + x − 12? (1 point)

Mathematics

2 answers:

kogti [31]3 years ago

8 0

Answer:

-8

Step-by-step explanation:

Multiply the brackets (2x - 4)

Add the x constant together (4x + 2x - 4x - x)

Add the other numbers together (4-12)

x = -8

Have a good day :)

Nostrana [21]3 years ago

6 0

The answer is x = -8

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Show that the series is convergent by the alternating series test, and find the number of terms necessary to estimate the sum of

Murljashka [212]

Answer:

6 terms

Step-by-step explanation:

2 − 2/4 + 2/9 − 2/16 + ...

∑ (-1)ⁿ⁺¹ 2 / n²

Applying alternating series test:

lim(n→∞) 2/n² = 0

2/(n+1)² < 2/n², so the series is decreasing.

Therefore, the series converges.

2/(n+1)² < 0.05

(n+1)²/2 > 20

(n+1)² > 40

n+1 > 6.32

n > 5.32

n = 6

7 0

3 years ago

Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)

JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

$a=46\\d=42-46=-4$

So , Let's calculate how many terms are there as :

⇒ $a_n=a +(n-1)d$

⇒ $-450=46 +(n-1)(-4)$

⇒ $-496=(n-1)(-4)$

⇒ $\frac{-496}{-4}=n-1$

⇒ $124=n-1$

⇒ $n=125$

Sum of an AP is :

⇒ $S_n = \frac{n}{2}(2a+(n-1)d)$

⇒ $S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))$

⇒ $S_1_2_5 = \frac{125}{2}(-404)$

⇒ $S_1_2_5 =-25,250$

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0

3 years ago

Read 2 more answers

A store has a $489.99 item on sale for 50% off. What is the discount on this item?

kondaur [170]

50% is 1/2 so 2 divided into $489.99 equals $244.995 or $244.99. Hope this helps!

3 0

4 years ago

Read 2 more answers

The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from

melomori [17]

Answer:

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=p$

$\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}$

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785$

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

8 0

4 years ago

Can you fill in the blanks. Thx

maria [59]

Answer:

Answer is below

Step-by-step explanation:

Download docx

4 0

3 years ago