help with this you guys i know im asking to many questions and sorry because im going to keep asking them.
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Answer:
0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they have a high school degree as their highest educational level, or they do not. The probability of an adult having it is independent of any other adult. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
30.4% of U.S. adults 25 years old or older have a high school degree as their highest educational level.
This means that
100 such adults
This means that
Determine the probability that the number who have a high school degree as their highest educational level is a. Exactly 32
This is P(X = 32).
0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.
Answer:
(a) Null Hypothesis, :
= 22 ounces
Alternate Hypothesis, :
22 ounces
(b) The value of the test statistic is -2.687.
(c) The critical values are -1.96 and 1.96.
(d) We conclude that Reject since the value of the test statistic is less than the negative critical value.
Step-by-step explanation:
We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.
He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.
<em>Let </em><em> = average ounces of passion fruit juice used to fill each bottle.</em>
(a) So, Null Hypothesis, :
= 22 ounces {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}
Alternate Hypothesis, :
22 ounces {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}
The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;
T.S. = ~ N(0,1)
where, = sample mean weight of the passion fruit juice = 21.54 ounces
= population standard deviation = 1.38 ounce
n = sample of bottles = 65
So, <u><em>test statistics</em></u> =
= -2.687
(b) The value of z test statistics is -2.687.
(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.
<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>
Therefore, we conclude that Reject since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.