You should know that cos2x =1-2sin^2x, so you substitute and take everything to one side. After that I took out a common factor of sinx which simplified my equation and gave me my first solution x=0. I go and find the relative acute angle in my second solution 2sinx+1=0, and as the value of raw is negative you have to obtain two solutions from where sin is negative. And you are given all you solutions. Hopefully this helps, if you don’t understand what I am saying just ask me anything. :)
You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.
Answer:
x=-11.9
Step-by-step explanation:
Substitute the value for y as 450
450=-5x+1
Solve for x
450-1=-5x
449=-5x
89.8=-x
x=-89.8
43.7%
<span>
Difference = 115 - 87 = $0.38
Use 87 as the base because that's the price to start
38/87 = 0.43678</span>
