Factor the following trinomial

qwelly [4]

Answer:collecting data

Step-by-step explanation:

7 0

3 years ago

An empty box weighs 200g the box is filled with birthday party goozy bags and now weighs 6.2kg Each goody bag weighs 150Work out

otez555 [7]

For this case, the first thing we are going to do is define variables.
We have then:
x: number of birthday party goozy bags
y: total weight
We then have the following equation:
y = 150x + 200
For y = 6200 we have:
6200 = 150x + 200
Clearing x:
x = (6200-200) / (150)
x = 40
Answer:
there are 40 goody bags inside the box

5 0

3 years ago

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y <

levacccp [35]

<u>Solution-</u>

The given inequalities are,

$y < 2x-7,\\\\y\geq-\frac{1}{2}x+3$

As the former inequality is only '<' so it will be represented as dotted line, but in case of the later inequality there is '≥' so it will be represented as a solid line.

This happens because in only '<, >' the values must be either lesser or greater than y, they can't take the values of y, but in case of '≤, ≥' the values can be equal to y.

Taking origin (0, 0) and putting in the first inequality.

$\Rightarrow 0< 2(0)-7\\\\\Rightarrow 0\nless -7$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

Again taking origin (0, 0) and putting in the second inequality.

$\Rightarrow 0\geq-\frac{1}{2}0+3\\\\\Rightarrow 0\ngeqslant 3$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

The second attachment contains the feasible region.

In order to know whether the point (3, −7) is included in the solution area for the system or not, we must put it in both the equations, if it satisfies both then only it is within the solution area.

$\Rightarrow -7< 2(3)-7,\ -7\geq-\frac{1}{2}(3)+3\\\\\Rightarrow -7$

As the point (3, -7) only satisfies first inequality, but not the second inequality so this point won't be in the solution area.

6 0

3 years ago

Read 2 more answers

Find the distance to the nearest tenth,between S(6,5) and T(-3,-4)

Doss [256]

Answer:

<h3>The answer is 12.7 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(6,5) and T(-3,-4)

The distance between them is

$|ST| = \sqrt{ ({6 + 3})^{2} + ({5 + 4})^{2} } \\ = \sqrt{ {9}^{2} + {9}^{2} } \\ = \sqrt{81 + 81} \\ = \sqrt{162} \\ = 9 \sqrt{2} \: \: \\ = 12.7279...$

We have the final answer as

<h3>12.7 units to the nearest tenth</h3>

Hope this helps you

6 0

3 years ago

please help me with it and dont just put random letters cause i dont know why u do it its not like u can buy a house with these

BartSMP [9]

Answer:

v=432cm

sA=144cm

Step-by-step explanation:

1)))

v=w*d*h

v=3*9*16

v=432cm

2)))

sA=h*w

sA=16*9

sA=144cm

6 0

3 years ago

Read 2 more answers