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jonny [76]
3 years ago
10

9 is 1/3% of what number?

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0
27 is the answer I believe
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In a random sample of 8 ​people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.4 minutes. A 90
konstantin123 [22]

Answer:

Margin of Error = 5.4088 ;

Confidence interval = (30.1 ; 40.9)

Interval estimate are almost the same

Step-by-step explanation:

Given that :

Population standard deviation, σ = 9.3

Sample size, n = 8

Xbar = 35.5

Confidence level = 90%

The confidence interval:

Xbar ± Margin of error

Margin of Error = Zcritical * σ/sqrt(n)

Zcritical at 90% = 1.645

Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088

Confidence interval :

Xbar ± Margin of error

35.5 ± 5.4088

Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1

Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9

(30.1 ; 40.9)

T distribution =. (30.5 ; 40.5)

Normal distribution = (30.1, 40.9)

4 0
3 years ago
Classify triangle BCD based on side lengths, given:
Pavel [41]

AB = BE = 5

BD = BE + ED = 5 + 3 = 8

BC = 8

BD = BC

CD = 5 which is not equal to 8.

Triangle BCD has exactly 2 congruent sides.

Answer: Triangle BCD is isosceles.

8 0
3 years ago
Read 2 more answers
Change the inequalities below to get 'y' by itself.(Please help me. I don't get how to do inequalities.)
astra-53 [7]

Answer:

y < x - 4

Step-by-step explanation:

First, move the x over to the other side by subtracting x from both sides. This will get you -y > -x + 4.

Divide both sides by -1 to get rid of the -1 in front of y. Since this is an inequality, dividing or multiplying by a negative number means that you have to flip the sign. We are dividing by a negative number, so flip > to <. The signs on both sides change to get y < x - 4.

6 0
3 years ago
Read 2 more answers
Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su
Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0
3 years ago
Can someone answer this pls
pashok25 [27]
The first should be 80 the second part of it should be 210 idk if thats completely right sorry if I'm wrong i hope i helped a little
7 0
3 years ago
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