Answer:
360 percent. 360 percent probability i think
Answer:
4
Step-by-step explanation:
you must scale down to size- 1 m in real life = 5 (unit) in the model
20/5= 40
hope this helps :)
The ball will bounce 72 cm high if dropped from a height of 120 cm
<u>Solution:</u>
Given, The height that a ball bounces varies directly with the height from which it is dropped.
A certain ball bounces 30 cm when dropped from a height of 50 cm.
We have to find how high will the ball bounce if dropped from a height of 120 cm?
Now, according to given information,
When dropped from 50 cm ⇒ bounces 30 cm
Then, when dropped from 120 cm ⇒ bounces "n" cm
Now by Chris cross method, we get,

Hence, the ball bounces 72 cm high.
Answer is 4 - x^2 = -16 so the answer is -8 for x.
Answer:
vertex point at (-2|11)
f(x)=-2*((x+2)^2+1*-11/2) (simplified)
Step-by-step explanation:
f(x)=-2*x^2+-8*x+3
f(x)=-2*(x^2+4*x+-3/2) ( Factor out )
f(x)=-2*(x^2+4*x+(2)^2+-1*(2)^2+-3/2) ( Complete the square )
f(x)=-2*((x+2)^2+-1*(2)^2+-3/2) ( Use the binomial formula )
hope this helped, I didn't get much to work with so if i'm wrong i'm sorry