Answer:
B. 
Step-by-step explanation:
We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

Substitute the values:





Therefore, the body surface area of the person would be 1.83 square meters.
To find of a cone

hope this help you
may i got a brainliest please

Because

is singular, we have

from which it follows that either

or

.
Answer:
A.27
B.6
Step-by-step explanation:
A. -3(9)=27
B.9/-3+9=-3+9=6
Plug in what its says a and b is equal to
1 triangle, it would be an equilateral one.