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3 years ago

Which of the following correctly shows the quadratic formula?

Mathematics

2 answers:

Gre4nikov [31]3 years ago

7 0

The first option is the correct quadratic formula

muminat3 years ago

3 0

Answer:

A) x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Step-by-step explanation:

The general form a quadratic equation y = $ax^2 + bx + c, where a \neq 0.$ .

We use quadratic formula when we find the solution of a quadratic equation.

The quadratic equation has two solutions.

x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Therefore, the answer is A) x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

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Solve 2x – 7 > 11.

BaLLatris [955]

Answer:

x > 9

Step-by-step explanation:

2x - 7 > 11

2x > 18

x > 9

5 0

3 years ago

What's the answer to -7=c-6

son4ous [18]

Simple...

you have: -7=c-6

You want to isolate the variable c

-7=c-6

-7=c-6
+6 +6

-1=c

Thus, your answer.

6 0

3 years ago

HELP PLEASE <br> solve the right triangle

aleksandrvk [35]

Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

7 0

3 years ago

I need these by today help

yulyashka [42]

Answer:

Step-by-step explanation:

-4, -2, 0, 4, 10

-2.9, -2.83, -2.09, 2.07, 2.56

-3, -1/10, 1/10, 1/2, 7/8

-3, -2, -0.8, -1/10, 1/2, 0.8, 7

this image might help :))

8 0

2 years ago

Read 2 more answers

Consider the quadratic function f(x) = –2x2 5x – 4. the leading coefficient of the function is?

evablogger [386]

Answer:

$\text{-2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

Step-by-step explanation:

Given the quadratic function

$f(x)=-2x^2+5x-4$

we have to find the leading coefficient of given quadratic equation.

$\text{The general form of quadratic equation is }ax^2+bx+c=0$

The coefficient of $x^2$ i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

$\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

3 0

3 years ago

Read 2 more answers