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PSYCHO15rus [73]
2 years ago
5

Please help, I really struggle with this! anythibg will help​

Mathematics
2 answers:
DaniilM [7]2 years ago
7 0
Answers:
1) 3/8 + 3/6 = 7/8

3/8 + 3/6
Simplify

3/4 + 1/2
Transform the expression

3 + 4/8
Calculate

=7/8
_____________

2) 5/9 + 1/3 = 8/9

5/9 + 1/3
Transform the expression

5 + 3/9
Calculate

= 8/9
_____________

3) 5/12 + 7/8 = 31/24

5/12 + 7/8
Transform the expression

10 + 21/24
Calculate

= 31/24
_____________

4) 7/9 - 1/6 = 11/18

7/9 - 1/6
Transform the expression

14 - 3/18
Calculate

= 11/18
_____________

5) 4 2/5 + 2 1/5 = 33/5

4 2/5 + 2 1/5
Convert the number

22/5 + 11/5
Calculate

22 + 11/5
Calculate

= 33/5
_____________

6) 5 3/8 + 2 7/8 = 33/4


5 3/8 + 2 7/8
Convert the number

43/8 + 23/8
Calculate

43 + 23/8
Calculate

= 66/8
Katena32 [7]2 years ago
7 0
<h3>Question 1 :- </h3>

{:\implies \quad \sf \dfrac{3}{8}+\dfrac{3}{6}}

After taking LCM ;

{:\implies \quad \sf \dfrac{9+12}{24}}

{:\implies \quad \sf \dfrac{21}{24}}

{:\implies \quad \bf \underline{\underline{\dfrac{7}{8}}}}

<h3>Question 2 :- </h3>

{:\implies \quad \sf \dfrac{5}{9}+\dfrac{1}{3}}

After taking LCM ;

{:\implies \quad \sf \dfrac{5+3}{9}}

{:\implies \quad \bf \underline{\underline{\dfrac{8}{9}}}}

<h3>Question 3 :- </h3>

{:\implies \quad \sf \dfrac{5}{12}+\dfrac{7}{8}}

After taking LCM ;

{:\implies \quad \sf \dfrac{10+21}{24}}

{:\implies \quad \bf \underline{\underline{\dfrac{31}{24}}}}

<h3>Question 4 :- </h3>

{:\implies \quad \sf \dfrac{7}{9}-\dfrac{1}{6}}

After taking LCM ;

{:\implies \quad \sf \dfrac{14-3}{18}}

{:\implies \quad \bf \underline{\underline{\dfrac{11}{18}}}}

<h3>Question 5 :- </h3>

{:\implies \quad \sf 4\dfrac{2}{5}+2\dfrac{1}{5}}

Simplifying it into improper fraction will leave with us ;

{:\implies \quad \sf \dfrac{22}{5}+\dfrac{11}{5}}

Now , we know that whenever we add or subtract two or much fractions and their <em><u>denominator is same</u></em> , then the resultant has the <em><u>same denominator</u></em> and we had to perform operations in just numerator .

Applying it here ;

{:\implies \quad \bf \underline{\underline{\dfrac{33}{5}}}}

<h3>Question 6 :- </h3>

{:\implies \quad \sf 5\dfrac{3}{8}+2\dfrac{7}{8}}

Simplifying it into improper fraction will leave with us ;

{:\implies \quad \sf \dfrac{43}{8}+\dfrac{23}{8}}

{:\implies \quad \sf \dfrac{43+23}{8}}

{:\implies \quad \sf \dfrac{66}{8}}

{:\implies \quad \bf \underline{\underline{\dfrac{33}{4}}}}

<em><u>Note :-</u></em> Whenever we have a mixed fraction of the form {\bf a\dfrac{b}{c}} we convert it into <em><u>an improper fraction</u></em> of the form {\bf \dfrac{ac+b}{c}}

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Marco had sales of $28,000. He makes a graduated commission of 4% on the first $10,000, 5% on the next $20,000 and 6% on anythin
Paha777 [63]

Answer:

$1,300

Step-by-step explanation:

commission on the first $10,000

= 4/100 * 10000

= $400

remaining amount

= $28,000 - $10,000

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commission on remaining $18,000

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7 0
2 years ago
Math work pls help :)​
AveGali [126]

Answer:

History of mathematics

Several civilizations — in China, India, Egypt, Central America and Mesopotamia — contributed to mathematics as we know it today. The Sumerians were the first people to develop a counting system. Mathematicians developed arithmetic, which includes basic operations, multiplication, fractions and square roots. The Sumerians’ system passed through the Akkadian Empire to the Babylonians around 300 B.C. Six hundred years later, in America, the Mayans developed elaborate calendar systems and were skilled astronomers. About this time, the concept of zero was developed.

Step-by-step explanation:which includes basic operations, multiplication, fractions and square roots. The Sumerians’ system passed through the Akkadian Empire to the Babylonians around 300 B.C. Six hundred years later, in America, the Mayans developed elaborate calendar systems and were skilled astronomers. About this time, the concept of zero was developed.

7 0
3 years ago
5-2(x+5)=3x-15 solve for X
Maslowich

Answer:

x= 2

Step-by-step explanation:

5 -2(x +5)= 3x -15

Expand:

5 -2x -2(5)= 3x -15

5 -2x -10= 3x -15

Simplify:

-2x -5= 3x -15

Bring x terms to 1 side, constant to the other:

3x +2x= 15 -5

5x= 10

Divide both sides by 5:

x= 10 ÷5

x= 2

8 0
3 years ago
Read 2 more answers
PLZ HELP!!!!! WILL MARK!!!
Alex777 [14]
4x^2 +15x + 13 tyats would be tour answrr
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in a geometrical progression,the product of the 2nd and 4th term is double the the 5th terms. and the sum of the first four term
ahrayia [7]

Answer:

solve by your self dont depend on other!

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3 years ago
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