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kolbaska11 [484]
3 years ago
9

2. Josh has m marbles. Matthew has 5 more than triple the number of marbles that Josh has. In terms of m, how many marbles does

Matthew have?​
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0
3m+5
Josh’s marbles can be represented by m
Matthew’s marbles can be represent by 3m+5 (the 3m is for triple what Josh has which is m)
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vekshin1

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There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the solution has an intersection with an infinite number of solutions.

Step-by-step explanation:

Its right on edg

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Look at the row of numbers. What number should come next?<br> 8, 4, 2, 1, 1/2, 1/4, ?
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Left 7 down 6 Then count two spaces left right up and down and draw a circle

Step-by-step explanation:

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What is the solution, if any, to the inequality |3x|2O?
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Step-by-step explanation:

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goblinko [34]

Answer:

Step-by-step explanation:

Combine like terms. Like terms have same variable with same power

a) (2xy + 4x) + (15xy - 5x)  = <u>2xy + 15xy</u> +<u> 4x - 5x</u>

                                         = 17xy - x

b) (6a + 4b² - 3) + (3b² - 5) = 6a + <u>4b² + 3b²</u>  <u>- 3 - 5 </u>

                                           = 6a + 7b² - 8

c) (4x³ - 3x² +4x) + (8x² - 5x ) = 4x³ <u>- 3x² + 8x²</u>  <u>+ 4x - 5x</u>

                                               = 4x³  + 5x² - x

d) (7b - 6a  + 9y) - (12b + 5a - 2y) =

In subtraction, add the additive inverse of (12b + 5a - 2y)

additive inverse = - 12b  - 5a  + 2y

(7b - 6a  + 9y) - (12b + 5a - 2y) = 7b - 6a + 9y  -12b -5a + 2y

                                                   = 7b - 12b  -6a - 5a  + 9y + 2y

                                                   = -5b - 11a + 11y

e) (2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)

Additive inverse of  13x + 4x² + 5 - 6y = -13x + 4x² - 5 + 6y

(2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)= 2x² + 7x - 2 + 9y -13x - 4x² -5 +6y

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                    = -2x²  - 6x  - 7 + 15y

5 0
3 years ago
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