3 years ago

Help please Number 4!!! Please show me how you did it!!

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

I can’t see nothing

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Two-step equation<br> 2x+5x=-1<br> What's the answer for x=

xxTIMURxx [149]

-1 / 7 = x

You need to combine the 2x and 5x then devise the 7x from -1

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5/6(1/2(12)+6)-3(12)

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-26

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1/3 + 1/4=

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X + 4y = 23<br> -3x = 12y + 1<br> is it no solution?

bagirrra123 [75]

Answer: Yes

Step-by-step explanation:

First multiply the first equation by three to get 3x+12y=69

Then subtract 12y from both sides of the second equation

Then add the first system and the second like this:

$3x+12y=69\\-3x-12y=1\\--------\\0+0=70\\0=70$

Because 0≠70, the system has no solutions

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3 years ago

A circle with center (4 -3) contain the point (9,-3). what is an equation of the circle

torisob [31]

Answer:

$\large\boxed{(x-4)^2+(y+3)^2=25}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the center (4, -3) and the point on the circle (9, -3).

The length of radius is equal to the distance between a center and an any point on a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Susbtitute:

$r=\sqrt{(9-4)^2+(-3-(-3))^2}=\sqrt{5^2+0^2}=\sqrt{5^2}=5$

The center (4, -3) → h = 4, k = -3.

Finally we have:

$(x-4)^2+(y-(-3))^2=5^2\\\\(x-4)^2+(y+3)^2=25$

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3 years ago