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lesya [120]
3 years ago
13

Can someone help me Q. 15 - 19

Mathematics
2 answers:
lianna [129]3 years ago
6 0

Answer:

negative

4 -4

Step-by-step explanation:

kramer3 years ago
6 0
Negative 4-4 hope this helps
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Rewrite the following as a mix numbers 17/3
barxatty [35]

answer is 5 2/3.............

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4 years ago
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What is the range of the function y=3√x+8?<br> O-∞ O-8 O 0≤y&lt;∞<br> O 2≤y&lt;∞
Ket [755]

Answer: 0 ≤ y < ∞

Step-by-step explanation:

   First, let us graph the function. See attached.

-><em> If I graphed the formatting of the square root sign incorrectly, please let me know so I can fix the answer.</em>

<em />

  The range of the function is all of the function's output values. In this case, all of the y values.

        0 ≤ y < ∞

5 0
2 years ago
EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If
amm1812

Answer:

To Prove: 9e^x is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If f(x) = 9e^x, then f ^{(n + 1)(x)} =9e^x for all n. If d is any positive number and   |x| ≤ d, then |f^{(n + 1)(x)}| = 9e^x\leq  9e^d.

So Taylor's Inequality, with a = 0 and M = 9e^d, says that |R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq  d.

Notice that the same constant M = 9e^d works for every value of n.

But, since lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$,

We have lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0

It follows from the Squeeze Theorem that lim_{n\to\infty} |R_n(x)|=0 and therefore lim_{n\to\infty} R_n(x)=0 for all values of x.

THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and  $ lim_{n\to\infty} R_n(x)=0 \:  for \: |x-a|

By this theorem above, 9e^x is equal to the sum of its Maclaurin series, that is,

9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}  for all x.

6 0
3 years ago
.A retailer sold two articles at same price. He sold the first one at 10% profit and the
IRISSAK [1]

Step-by-step explanation:

so let's assume they both sold for 100 each the first article sold for 10% laws there by cost of article is 111.11 rounded the second article made 25% profit so cost must be 80 total cost is 8.89 or 5% profit I'm so sorry if im wrong

3 0
3 years ago
What is the length of segment TQ.
Jobisdone [24]

Answer:

C )  14 units

Step-by-step explanation:

I am assuming this is the problem's image? If not, please let me know and I will do a different one. I hope this helps!

We know QV = 15 and TQ = TS, QV = SV;

4 x - 1 = 15

4 x = 15 + 1

4 x = 16

x = 16 : 4 = 4

so,

TQ = 3 * 4 + 2 = 12 + 2 = 14

Answer:

C )  14 units

3 0
3 years ago
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