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Vesna [10]
4 years ago
10

Factor 2d^2-8de+6e^2

Mathematics
1 answer:
Amanda [17]4 years ago
6 0
The answer is .... 2 (d^2 - 4de + 3e^2 )
have a great day!!!





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PLEASE HELP!
Oliga [24]

Answer:

C. 8/30 is your answer.

Step-by-step explanation:

What you do is you take each fraction and make it into a decimal.

6/24 = .25

We know that 1/4 is .25.

5/20 and 12/48 are also .25.

C. 8/30 is your answer.

3 0
4 years ago
Arnav knows that (3, 4, 5) and (5, 12, 13) are Pythagorean triples. He wants to show that (15, 20, 25) is also a Pythagorean tri
stira [4]

9514 1404 393

Answer:

  multiply the (3, 4, 5) triple by 5 to get (15, 20, 25)

Step-by-step explanation:

Any multiple of a Pythagorean triple is a Pythagorean triple.

  5(3, 4, 5) = (5·3, 5·4, 5·5) = (15, 20, 25) — a Pythagorean triple

6 0
3 years ago
Li uses 8.4 grams of sugar every day in her tea. Sue uses 12.6 grams of sugar every day in her coffee. If Li’s sugar canister co
podryga [215]

Answer:

They will have the same amount of sugar in their canisters in 15 days

Step-by-step explanation:

Here in this question, we are concerned with knowing the number of days in which the amount of sugar in both canisters will be the same.

Since we do not know the number of days it will

take, we have to represent it using a variable.

Let the number of days be x days

Now, we are told Li uses 8.4 g per day.

So in x days, the amount user will be 8.4 * x = 8.4x g

Thus, the amount of sugar remaining in her canister after x days will be 128 - 8.4x

For Sue, she uses 12.6 grams each day. So in x days, the amount of sugar used will be 12.6 * x = 12.6x g

So the amount of sugar left in her canister will be 191-12.6x

Since on the xth day , the amount of sugar remaining is same, we can equate the amount of sugar remaining in both canisters. That would be;

128-8.4x =191-12.6x

Collect like terms;

12.6x-8.4x = 191-128

4.2x = 63

x = 63/4.2

x = 15 days

6 0
4 years ago
HELP PLEASE I NEED TO TURN THIS IN BEFORE WEDNESDAY
JulijaS [17]

Answer:

451

Step-by-step explanation:

4 0
3 years ago
A line has a slope of -1 and contains the points (1, 2) and (2, y). The value of y is
Salsk061 [2.6K]

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{y}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-2}{2-1}=\stackrel{\stackrel{slope}{\downarrow }}{-1} \\\\\\ \cfrac{y-2}{1}=-1\implies y-2=-1\implies y=1

4 0
3 years ago
Read 2 more answers
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