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DiKsa [7]
3 years ago
12

Solve t^2a=t^2e−r for t

}e-r" alt="t^{2}a=t^{2}e-r" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

\bf t^2a=t^2e-r\implies t^2a-t^2e=-r\implies t^2(a-e)=-r \\\\\\ t^2=\cfrac{-r}{a-e}\implies t=\pm\sqrt{\cfrac{-4}{a-e}}

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