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Sveta_85 [38]
3 years ago
15

What transformations are represented by the following coordinate graphing? (geometry)

Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

(a,b) → (a,-b) : Reflection about x axis.

(a,b) → (a, b+5) : Translation of the point by 5 units up.

(a,b) → (b,-a) : Rotation by 90 degree clockwise.

Step-by-step explanation:

Given:

The transformation of points are given as:

(a,b) → (a,-b)

(a,b) → (a, b+5)

(a,b) → (b,-a)

Now, let us consider each transformation one by one.

(1) (a,b) → (a,-b)

Here, the order of the coordinates has not changed. But, the y coordinate of the point has changed. The y coordinate was 'b' and it has changed only its sign but not value. So, it is a transformation related to reflection.

In reflection, only the sign changes. Since, the 'y' coordinate sing is reversed, so, it is a reflection about x axis.

(2) (a,b) → (a, b+5)

Here, the 'y' coordinate of the point has changed. The change is from 'b' to 'b+5'. So, 5 is added to the y coordinate. As per transformation rules, if a positive number 'C' is added to the y coordinate, then the point shifts vertically up by 'C' units. Hence, there is a translation of 5 units up here.

(3) (a,b) → (b,-a)

Here, the 'x' and 'y' coordinates interchange their values and also the new y coordinate has its sign reversed. This happens in rotation.

We know that, (x, y) → (y, –x) is true when there is rotation by 90 degree clockwise.

So, the point (a,b) → (b,-a) is rotated by 90 degree clockwise.

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We have that for the Question,it can be said that these the various <em>graphs</em> and polynomials have the following deductions

1)

Even degree

<em>Negative </em>leading <em>coefficient</em>

  • Second graph

2)

Odd degree

Positive leading <em>coefficient</em>

  • 1st Graph

3)

The end behaviour of the 14th diploma <em>polynomial </em>is that it will increase to infinity.

4)

The <u>polynomial</u> will have a tendency to infinity.

Generally

The end behavior of a <em>polynomial </em><u>gra</u>ph draws reference from the starting <em>direction </em>and its end direction or the <em>ends </em>of the x axis

Where

Graph 1

f(x)= -\infty (Left)\\\\f(x)= +\infty (Right)

A Graph of even or odd degree bears the following lead co-efficient characteristics

Even

f(x) -> \infty \ as x -> \pm \infty  \\\\f(x) -> -\infty \ as x -> \pm \infty

Odd

f(x) -> -\infty \as x -> - \infty\\\\f(x) -> \infty \ as x ->  \infty

Therefore

  • 1st Graph

Positive leading <em>coefficient</em>

Odd degree

  • Second graph

<em>Negative </em>leading <em>coefficient</em>

Even degree

3)

Even Numbered degree <u>typically </u>have the <em>identical</em> give up behavior for the two ends. This his due to the fact that if N is a entire number,

-A^2=A^2  

Due to the fact the Leading <em>coefficient </em>is positive, and a variety with an even exponent is additionally positive,  end behaviour of the 14th diploma <em>polynomial </em>is that it will increase to infinity.

4)

The ninth degree polynomial  as we have a leading <em>coefficient </em>and a abnormal exponent.  

Then as x tends to infinity, the polynomial will have a <em>tendency</em> to terrible infinity. as x tends to -ve<u> </u>infinity, the <u>polynomial</u> will have a tendency to infinity.

For more information on this visit

brainly.com/question/12021944

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