Answer:
Kilogram of chicken = 1
Kilogram of tilapia = 3
Step-by-step explanation:
Cost of chicken = 150 per kilo
Cost of tilapia = 100 per kilo
Number of kilos of each if total cost should not exceed 450
Let :
Number of kilo of chicken = x
Number of tilapia kilo = y
The constraint :
150x + 100y ≤ 450
We could choose some reasonable values of x and y then, test the constraint ;
If x = 1 and y = 3
150(1) + 100(3) = 450
Hence,
1 kilo of chicken with 3 kilos of tilapia offers the greatest combination of Number of kilograms of tilapia and chicken that could be purchased and still satisfy the maximum cost constraint.
B: because 11 times N will give you how much your cost would be . Example: 11*2= $22 if you bought 2 cds it would be $22. and its continuous cause youre going up at a constant rate.
Answer:
x < -6
Step-by-step explanation:
18 + x < 12
Subtract 18 from each side
18-18 + x < 12-18
x < -6
is the formula you need do you divide 47.1 by 2 and
so its aproximatly 7.5 or 7.496
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
