By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
<h3>How to evaluate a piecewise function at given values</h3>
In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:
<h3>r(- 3): </h3>
-3 ∈ (- ∞, -1]
r(- 3) = - 2 · (- 3) + 9
r (- 3) = 15
<h3>r(- 1):</h3>
-1 ∈ (- ∞, -1]
r(- 1) = - 2 · (- 1) + 9
r (- 1) = 11
<h3>r(1):</h3>
1 ∈ (-1, 5)
r(1) = 2 · 1² - 4 · 1 - 5
r (1) = - 7
<h3>r(5):</h3>
5 ∈ [5, + ∞)
r(5) = 4 · 5 - 7
r (5) = 13
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
To learn more on piecewise functions: brainly.com/question/12561612
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1. Make y the subject of the equation
y = -4 - 6x
2. Substitute values for guess and check
8 = -4 - (6 x 2)
8 = -4 - 12
This is incorrect.
2 = -4 - (6 x 1)
2 = -4 -6
This is incorrect.
-10 = -4 - (6 x 1)
-10 = -4 -6
This is correct.
The correct answer is C.
the answer is the third one on the page that is it my dude
The functin f(x) = 2^x is an exponential function.
It does not have vertical asymptotes because the function is defined for all the real values.
To find the horizontal asymptotes calculate the limits when the function grows positively and negatively.
The limif of 2^x when x goes to + infinity is infinity so there is not asymptote to this side.
The limit of 2^x when x goes to - infinity is 0, so y = 0 is an asymptote.
Answer: the equation for the asymptote is y = 0.
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