Need help on this lowkey

Mathematics

1 answer:

Alik [6]3 years ago

7 0

Problem 42 is 4 because 2(3+4)= 14 So 2x3 is 6. (14-6=8) so them 2x4 is 8.

Problem 43 is 6 because 5(6+3)= 45 So 5x3 is 15 (45-15=30) and 5x6=30

In problem 44 7x4=28 and 4x5=20 so you do 28+20 to get 48. (48 divided by 4 is 12) So 12-7 is 5. 5 is the answer

Problem 45: 6x4=24 and 6x3=18. 24+18=42. (42 divided by 6 is 7) so the last one could be anything added together to make 7.
Ex: 6+1 5+2 4+3

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Find x.<br><br> See attached picture.

pishuonlain [190]

Answer:

B. 22

Step-by-step explanation:

We know tan60=

$\sqrt{3}$

Let common side be x

Tan = opp/adj= sqrt(3)

$\frac{11 \sqrt{6} }{x} = \sqrt{3}$

Transposing we get :

$\frac{11 \sqrt{6} }{ \sqrt{3}} = x = 11 \sqrt{2}$

Now, we know that since the other triangle is a 45-45-90 triangle, we can state that the side adjacent to the given angle = 11 sqrt(2) as the two sides are equal due to the triangle being an isoceles triangle.

Solve for x by using Pythagorean theorem:

$\sqrt((11 \sqrt{2}^{2} + (11 \sqrt{2} )^{2} ) = x$