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Black_prince [1.1K]
3 years ago
12

Choose the correct graph for the equation y=2x+3

Mathematics
2 answers:
jasenka [17]3 years ago
6 0

Answer:

Step-by-step explanation:

disa [49]3 years ago
5 0

Answer:

Step-by-step explanation:

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Abbot Tools is designing a new toolbox. The length of the toolbox will be three times its width, w, and the length of the diagon
Ilia_Sergeevich [38]

The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.

<h3>Triangle</h3>

  • Width of the triangle = w
  • Length of the triangle = 3w
  • Diagonal = 30 inches

Hypotenuse ² = opposite ² + adjacent ²

30² = w² + (3w²)

30² = 4w²

900 = 4w²

w² = 900/4

= 225

w = √225

w = 15

Therefore,

Width of the triangle = w

= 15 inches

Length of the triangle = 3w

= 3(15)

= 45 inches

Learn more about triangles:

brainly.com/question/24382052

#SPJ1

5 0
2 years ago
X - y = 8
HACTEHA [7]

slope intercept form

y = mx +b

x-y =8

subtract x from each side

-y = -x+8

divide by -1

y = x-8

Choice C

8 0
3 years ago
1. In AABC, if a = 8, b = 2, and c = 7. What is the value of cos C?
jenyasd209 [6]
I’m a little confused do you have a picture I could solve for cos then
4 0
3 years ago
Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or
NARA [144]

Answer:

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

Step-by-step explanation:

The function is:

f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y

The partial derivatives of the function are included below:

\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y

\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)

\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x

\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)

Local minima, local maxima and saddle points are determined by equalizing  both partial derivatives to zero.

y \cdot (8\cdot y -16\cdot x + 9) = 0

x \cdot (16\cdot y - 8\cdot x + 9) = 0

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

x\cdot (-8\cdot x + 9) = 0

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

y\cdot (8\cdot y+9) = 0

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}

The second derivatives of the function are:

\frac{\partial^{2} f}{\partial x^{2}} = 0

\frac{\partial^{2} f}{\partial y^{2}} = 0

\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9

Then, the expression is simplified to this and each point is tested:

H = -16\cdot y +16\cdot x -9

S1: (0,0)

H = -9 (Saddle Point)

S2: (3/8,-3/8)

H = 3 (Local maximum or minimum)

S3: (9/8, 0)

H = 9 (Local maximum or minimum)

S4: (0, - 9/8)

H = 9 (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64} (Local minimum)

S3: (9/8, 0)

f(\frac{9}{8},0) = 0 (Local maximum)

S4: (0, - 9/8)

f(0,-\frac{9}{8} ) = 0 (Local maximum)

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

4 0
3 years ago
Jake drew an isosceles right triangle. What are the measures of the two acute angles? How do you know?
scoray [572]
SO you know that triangles add up to 180. A right angle equals 90 so 180-90=90. And an isosceles triangle means that 2 angles are congruent. SO 90/2 = 45. The measure of the 2 acute angles are 45
8 0
3 years ago
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