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katovenus [111]
3 years ago
12

en la siguiente exprecion un ejemplo de un termino semejante es x a la 2y-3x ala dosy+ 2xy a la dos-10xy a la dos

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

cada término puede ser un número o el producto de un número (en ocasiones un 1 implícito) y una o más variables.

Step-by-step explanation:

3 x 2 y + 2 xy – 9 x + 2.

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Please answer the questions(in the pictures) as fast as possible.
andrew-mc [135]

it is 2/3


0--4/6 =

4/6


5 0
3 years ago
consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations
emmasim [6.3K]

Answer:

x=1 and x=4

Step-by-step explanation:

We have the following system of equations:

y=\sqrt{x} and y=x-2

To solve the problem, we need to equal the two equations:

x-2=\sqrt{x} ⇒ (x-2)^{2} =x ⇒ x^{2} -4x + 4 = x  

⇒ x^{2} -5x + 4 = 0  

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are x=-1 and x=-4.

Then, the factorized form of the polynomial is: (x-1)(x-4).

The, the solution to the system of equations is: x=1 and x=4.

5 0
3 years ago
Find the values for c and d
baherus [9]

Answer:

c=-5

d=1

Step-by-step explanation:

(cy^2)(4y^d)=-20y^3

I'm going to reorder the left-hand side.  Multiplication is commutative.

(4c)(y^2y^d)=-20y^3

Since the bases are the same in y^2y^d and the operation is multiplication, I'm going to add the exponents giving me:

4cy^{2+d}=-20y^3

So this implies we have two equations to solve:

4c=-20 and 2+d=3

So the first equation can be solved by dividing both sides by 4 giving you c=-5.

The second equation can be solved by subtracting 2 on both sides giving you d=1.

6 0
3 years ago
4. Three hoses are connected end to end. The first hose is
Yuri [45]

Answer:7.25 feet

Step-by-step explanation:

6.25+6.5=12.75

20-12.75=7.25

4 0
3 years ago
Determine whether the following function is one-to-one. f ( x ) = 6 x + 1
seraphim [82]

Answer:

one to one function

Step-by-step explanation:

f(x)=6x+1 can only be a one to one function when x1=x2

Now,

f(x1)=f(x2)

or, 6x1 + 1 = 6x2 + 1

or, 6x1 = 6x2

or, x1 = x2

So f(x)= 6x + 1 is a one to one function

4 0
2 years ago
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