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kvasek [131]
3 years ago
10

Consider the following. f(x, y) = x/y, P(9, 1), u = 3 5 i + 4 5 j (a) Find the gradient of f. ∇f(x, y) = (b) Evaluate the gradie

nt at the point P. ∇f(9, 1) = (c) Find the rate of change of f at P in the direction of the vector u. Duf(9, 1) =
Mathematics
1 answer:
Verizon [17]3 years ago
3 0

f(x,y)=\dfrac xy

a. The gradient is

\nabla f(x,y)=\dfrac1y\,\vec\imath-\dfrac x{y^2}\,\vec\jmath

b. At the point (9, 1), the gradient has value

\nabla f(9,1)=\vec\imath-9\,\vec\jmath

c. The derivative of f at (9, 1) in the direction of \vec u=\dfrac35\,\vec\imath+\dfrac45\,\vec\jmath is

D_uf(9,1)=\nabla f(9,1)\cdot\dfrac{\vec u}{\|\vec u\|}

We have

\|\vec u\|=\sqrt{\left(\dfrac35\right)^2+\left(\dfrac45\right)^2}=1

so

D_uf(9,1)=(\vec\imath-9\,\vec\jmath)\cdot\left(\dfrac35\,\vec\imath+\dfrac45\,\vec\jmath\right)=-\dfrac{33}5

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