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podryga [215]
3 years ago
5

REALLY EASY NEED ANSWER BY 10:00 P. M. AND WILL GIVE BRAINLEIST. PLS HURRY IF YOU HAVE TIME PLEASE ANSWER OTHER QUESTIONS PLS TH

ANK YOU.
Write about a real-world situation that can be represented by the equation y=7x. Be sure to explain what the variables represent in the situation.
Mathematics
1 answer:
UNO [17]3 years ago
7 0

Answer:

for every cinnamon bun, 7 pennies were given to the orphanage.

x: amount given to orphanage

y: cinnamon bun

(hope you do well... i think this would work :/)

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Alexis sells season tickets to soccer games. The season tickets cost $225.75. She makes a commission of 16% on each sale. Last m
WITCHER [35]

Answer:

She earned $1517.04 last month

Step-by-step explanation:

Let us solve the question

∵ Alexis sells season tickets to soccer games

∵ The season tickets cost $225.75

∵ She makes a commission of 16% on each sale

→ Multiply 225.75 by 16% to get her commission per ticket

∵ 16% = 16 ÷ 100 = 0.16

∴ Her commission per ticket = 0.16 × 225.75

∴ Her commission per ticket = 36.12 dollars

∵ Last month she sold 42 season tickets

∴ The number of tickets = 42

→ Multiply her commission per ticket by the number of tickets

∵ Her total commission = 42 × 36.12

∴ Her total commission = 1517.04 dollars

∴ She earned $1517.04 last month

3 0
3 years ago
Captain Umaima has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Nadia and her merciless band of thiev
brilliants [131]

Answer:

\frac{9}{35}.

Step-by-step explanation:

We have been given that captain Umaima has probability 3/7 of hitting the pirate ship.

The pirate only has one good eye, so she hits the Captain's ship with probability 2/5.

The probability that pirate misses the captain's ship will be:

\text{Probability that pirate misses captain's ship}=\text{1-probability that pirate hits captain's ship}    

\text{Probability that pirate misses captain's ship}=1-\frac{2}{5}  

\text{Probability that pirate misses captain's ship}=\frac{5}{5}-\frac{2}{5}

\text{Probability that pirate misses captain's ship}=\frac{5-2}{5}    

\text{Probability that pirate misses captain's ship}=\frac{3}{5}  

So the probability that pirate misses captain's ship will be 3/5.

Since both events are independent, so by the multiplication rule of probability we will get,

\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{3}{7}\times \frac{3}{5}

\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{3*3}{7*5}

\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{9}{35}

Therefore, the probability that the Captain hits the pirate ship, but the pirate misses will be \frac{9}{35}.

3 0
4 years ago
14 out of 56 people at a high school basketball
umka2103 [35]

Answer:

75%

Step-by-step explanation:

\frac{14}{56} *100=25

100-25=75

5 0
3 years ago
Read 2 more answers
How would I find x, I know it's an isosceles triangle but I so not know how to solve for it?????​
Wittaler [7]

Answer:

x=7 (if your teacher cares it could + or - 7)

Step-by-step explanation:

Okay, since it's a 90 degree triangle you can use the Pythagorean theorem

( a^2 + b^2 = c^2)

Since it's an isosceles triangle the other side is x because it's the same value.

x^2 + x^2= (7\sqrt{2} )^2

Add the left side

2x^2= 7^2 + \sqrt{2}^2 roots and square roots cancel each other out

So -> 2x^2= 49 x 2 =98

just solve for x.

x^2 = 98/2

x^2= 49

Square root both sides

x= 7

3 0
3 years ago
The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 118 inches, find the
IgorLugansk [536]
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
6 0
3 years ago
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