OPTION D = 2q is right answer
Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Answer:
-28
Step-by-step explanation:
y/3-x = x+9
x=5
=>y/3-5=5+9
=>y/-2=14
=>y = - 28
Answer:
6. 11.3 Miles
7. 1.5 Miles
8. No he would need 26 Miles , he only has 25 Miles.
9. 11.25 Miles
10. Not really it slightly goes over by about .80
