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Hunter-Best [27]
3 years ago
15

HELP!! claire has a hot tub with a diameter of 7 feet. she wants to purchase a cover to protect the hot tub. what is the area of

the cover? use pi =3.14 and round the answer to the nearest square foot. HELP PLEASE!!!!!!
Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0

Answer:I believe the answer is 38

Step-by-step explanation:

First, you must understand that since a hydromassage tub is mentioned and the diameter, it is assimilated that it is round in its upper part, which is why the formula is used to find the area of a circle

klemol [59]3 years ago
5 0

Answer:

The area  of the cover for the hot tub must be:

38 square feet.

Step-by-step explanation:

First, you must understand that since a hydromassage tub is mentioned and the diameter, it is assimilated that it is round in its upper part, which is why the formula is used to find the area of a circle:

Area of a circle = pi * radius ^ 2 (you must know that the radius is half the diameter)

Since the diameter is mentioned, it can be replaced in the formula:

Area of a circle = 3.14 * (3.5 feet) ^ 2

Area of a circle = 38,465 square feet. Approximately 38 square feet.

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15mm 12mm a= what is the length
Mrrafil [7]

Answer: The area is 180 square millimeters.

The length is 15 mm and the width is 12 mm. The length if the perimeter-- if you were going to ask that is

(2)(15) + 2(12)

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2r/5+7r/15= rewrite the expression by collecting like terms
kramer
<span>2r/5+7r/15=
LCM=15
(15\5=3*2r=6r)
15\15=1*7r=7r
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3 0
3 years ago
Read 2 more answers
What is the interquartile range of the data set?
anastassius [24]

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




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3 years ago
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