Question

Let a= x^2 +4. Rewrite the following equation in terms of a and set it equal to zero.

Answer 1

Answer:

C and G

Step-by-step explanation:

(x^2+4)^2+32=12x^2+48 is written as $(x^2+4)^2+32=12x^2+48$.

We can simplify the expression using the term a by replacing x^2 + 4 with a.

$(x^2+4)^2+32=12x^2+48\\(x^2+4)^2+32=12(x^2+4)\\a^2 + 32 = 12a\\a^2 - 12a + 32 = 0$

This factors into (a-4)(a-8). Solve by setting each factor equal to 0 and solve for a.

a-4 = 0                 a=4

a-8=0                   a=8