The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".

Calculating we have:

$TriangleArea=ABCE-ABCD\\\\TriangleArea=60cm^{2}-48cm^{2}=12cm^{2}$

Now, we can calculate "f" by using the formula to calculate the area of the triangle:

$TriangleArea=\frac{b*h}{2}\\\\TriangleArea=\frac{f*4cm}{2}\\\\12cm^{2}*2=f*4cm\\\\\frac{24cm^{2}}{4cm}=f\\\\f=6cm$

Now, finding "g" by using the formula to calculate the area of the rectangle, we have:

$RectangleArea=ABCD\\\\ABCD=Base*Height\\\\48cm^{2}=base*6cm\\\\base=g=\frac{48cm^{2}}{6cm}=8cm$

Hence, we have that:

$f=6cm\\g=8cm$

Have a nice day!

8 0

3 years ago

Kate wants to buy a new bicycle from a sporting goods store. The bicycle she wants normally sells for $360. The store has a sale

faust18 [17]

5/6 x 360 = 300
divide 360 by 6 = 60, then multiply 60 by 5 and you get 300.00

6 0

3 years ago