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3 years ago

How to put 1/2y=3/4x+.5 in standered form

Mathematics

1 answer:

Rufina [12.5K]3 years ago

5 0

Hope this helped! I’d appreciate brainless answer!

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It takes a new mail carrier 4 hours to deliver the mail on route a. It takes an experienced mail carrier 3 hours to do the same

Pani-rosa [81]

Answer: $\frac{12}{7}\ \text{hours}$

Step-by-step explanation:

Given

New mail carrier takes 4 hours for delivery i.e.

New mail carrier completes $\frac{1}{4}$ part of work in 1 hour

Old mail carrier takes 3 hours for delivery i.e.

mail carrier completes $\frac{1}{3}$ part of work in 1 hour

If they work together, they complete the work in x hours i.e.

$\Rightarrow \dfrac{1}{x}=\dfrac{1}{4}+\dfrac{1}{3}\\\Rightarrow \dfrac{1}{x}=\dfrac{3+4}{12}\\\Rightarrow x=\dfrac{12}{7}\ \text{hours}$

4 0

3 years ago

What is 16million ×64 no using calculator

SIZIF [17.4K]

<span>one billion twenty-four million</span>

6 0

3 years ago

Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $

yawa3891 [41]

Answer:

Step-by-step explanation:

Charlie has $27

He spent $3 for kid's meal for his little brother

Remaining money=27-3=$24

Number of Sandwiches he wants to buy = 6

Money he needs to pay for each sandwich = 24/6 = $4

8 0

2 years ago

The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p

Juliette [100K]

Check the picture below.

based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,

$\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)$

$\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}$

now, we can plug those values on A = (1/2)bh,

$\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5$

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3 years ago

Lamont lost 8 yards in the first quarter

beks73 [17]

The answer is -6 sorry could not explain because have to go somewhere hope it helped

3 0

2 years ago