PLZZZ HELP IM IN A RUSH
1 answer:
You might be interested in
Answer:
Slope of line is
Step-by-step explanation:
Given that the company logo has four concentric circles.
To plot the line on the graph take point as ( Diameter, Circumference )
Circumference of a circle is given by C=
Where D is the diameter.
To draw a line, we need at least two-point.
Now,
Take D=1
Circumference of a circle will be C=
Required point is (1,)
Take D=0
Circumference of a circle will be C=
Required point is (0,0)
The slope of line is given by s=
Hence,
s=
s=}{0-1}[/tex]
s=}{1}[/tex]
s=
Thus, Slope of line is
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
============================================================
Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
