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3 years ago

Select from the drop-down menus to correctly complete the sentence.

Mathematics

2 answers:

Brrunno [24]3 years ago

7 0

Answer: 1-right 2-down

Step-by-step explanation:

I took the test and got it right

wlad13 [49]3 years ago

4 0

Answer:

for anyone in the future that needs this the answer is The rule (x,y) ----> (x+2, y-4) represents a translation 2 units RIGHT and 4 units DOWN

Step-by-step explanation:

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Use the properties of exponents to rewrite the expression <br> 3•b•b•b•b•b•c•c•c•c•c

frosja888 [35]

$3\cdot b\cdot b\cdot b\cdot b\cdot b\cdot c\cdot c\cdot c\cdot c\cdot c =3b^5c^5$

3 0

2 years ago

Read 2 more answers

What is the volume of the square pyramid? Round to the nearest tenth.

Shkiper50 [21]

Answer:

1670.8 cm³

Step-by-step explanation:

Volume of square Pyramid = ⅓*a²*h

h = 15.3 cm

a = 18.1 cm

Plug in the values

Volume of the pyramid = ⅓*18.1²*15.3

Volume = 1670.81 ≈ 1670.8 cm³ (nearest tenth)

4 0

2 years ago

The perimeter of a triangle is 133 inches. If one side of the triangle is five more than the shortest side, and the longest side

barxatty [35]

133=x + (x+5) + (x+14)

133 = 3x+19

3x=114

x= 114/3 =38

5+38 =43

38+14 =52

check: 38 +43 +52 = 133

3 sides are : 38, 43 & 52

8 0

3 years ago

Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2

inna [77]

$(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)$

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

$6 x^{6}/3x = 2 x^{5} \\ \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\$

We repeat previous steps until we run out of numbers:
$3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2$
$\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}$

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
$(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )$

6 0

3 years ago

The area of a circular sun spot is growing at a rate of 1,200 km2/s.

Tpy6a [65]

A)

$\bf \textit{area of a circle}\\\\
A=\pi r^2
\\\\\\
\cfrac{dA}{dt}=\pi \cdot 2r\cfrac{dr}{dt}\implies \cfrac{dA}{dt}=2\pi r\cfrac{dr}{dt}\implies \cfrac{\frac{dA}{dt}}{2\pi r}=\cfrac{dr}{dt}\\\\
-----------------------------\\\\
\left. \cfrac{dr}{dt} \right|_{r=3000}\implies \cfrac{1200}{2\pi \cdot 3000}=\cfrac{dr}{dt}\\\\$

B)

$\bf A=\pi r^2\qquad A=490000\implies 490000=\pi r^2\implies \sqrt{\cfrac{490000}{\pi }}=r
\\\\\\
\left. \cfrac{dr}{dt} \right|_{r=\sqrt{\frac{490000}{\pi }}}\implies \cfrac{1200}{2\pi \cdot \sqrt{\frac{490000}{\pi }}}=\cfrac{dr}{dt}
$

8 0

2 years ago