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Mkey [24]
3 years ago
9

Which fraction is the largest 5/7 7/10 10/13 show how u worked out the answer

Mathematics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

3.1/13

Step-by-step explanation:

1.5/7 =0.214286

2.7/10=0.27

3.1/13 =0.238462

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4y + x = 12, 2x = 24 - 8y<br> Solve by Substitution
Ann [662]

Answer: Undefined

Step-by-step explanation:

4y+x=12, 2x=24-8y

Isolate x by subtracting 4y

4y+x=12

x=12-4y

Plug the equation for x in to anywhere you see the variable x in the other equation

2(12-4y)=24-8y

Distribute 2

24-8y=24-8y

Get the variables on one side so add 8y (cancels out)

24=24

Can’t solve its undefined

4 0
3 years ago
Please answer the question above.
Crank

Answer:

Waffle house :3

Step-by-step explanation:

8 0
2 years ago
Determine the intercepts of the line. 7x-5=4y-67x−5=4y−67, x, minus, 5, equals, 4, y, minus, 6 xxx-intercept: \Big((left parenth
sesenic [268]

Given:

The equation of line is

7x-5=4y-6

To find:

The x and y-intercept of the given line.

Solution:

We have,

7x-5=4y-6

Putting x=0, we get

7(0)-5=4y-6

Add 6 on both sides.

0-5+6=4y

1=4y

Divide both sides by 4.

\dfrac{1}{4}=y

So, the y-intercept is \left(0,\dfrac{1}{4}\right).

Putting y=0 in given equation, we get

7x-5=4(0)-6

Add 5 on both sides.

7x=-6+5

7x=-1

Divide both sides by 7.

x=\dfrac{-1}{7}

So, the x-intercept is \left(-\dfrac{1}{7},0\right).

4 0
3 years ago
Read 2 more answers
A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects
Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

                                       = 0.17228 + 0.17946 + 0.15328

                                       = 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0
3 years ago
Writing and Evaluating an Algebraic Expression Try it five more than the product of two and a number, decreased by seven; evalua
Mkey [24]

Answer:

7

Step-by-step explanation:

dont trust me i dont know the answer sry

5 0
3 years ago
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